City Q and City R are 498 km apart. At 1.28 p.m., Sean is travelling at a uniform speed left City Q for City R while Flynn set off from City R to City Q along the same road at a uniform speed, which was 10 km/h slower than that of Sean. The two met at 4.28 p.m.
- Find the speed of Sean.
- If Flynn continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Sean and Flynn to travel from 1.28 p.m. to 4.28 p.m. = 3 h
Average speed of Sean and Flynn
= 498 ÷ 3
= 166 km/h
Sean's speed
= (166 + 10) ÷ 2
= 176 ÷ 2
= 88 km/h
(b)
Flynn's speed
= 88 - 10
= 78 km/h
Distance that Flynn travelled in 3 h
= 3 x 78
= 234 km
Remaining distance that Flynn needed to travel
= 498 - 234
= 264 km
Time that Flynn needed to reach his destination after the two met
= 264 ÷ 78
= 3
3078 = 3
513 h
Answer(s): (a) 88 km/h; (b) 3
513 h