City E and City F are 534 km apart. At 4.18 p.m., Glen is travelling at a uniform speed left City E for City F while Howard set off from City F to City E along the same road at a uniform speed, which was 10 km/h slower than that of Glen. The two met at 7.18 p.m.
- Find the speed of Glen.
- If Howard continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Glen and Howard to travel from 4.18 p.m. to 7.18 p.m. = 3 h
Average speed of Glen and Howard
= 534 ÷ 3
= 178 km/h
Glen's speed
= (178 + 10) ÷ 2
= 188 ÷ 2
= 94 km/h
(b)
Howard's speed
= 94 - 10
= 84 km/h
Distance that Howard travelled in 3 h
= 3 x 84
= 252 km
Remaining distance that Howard needed to travel
= 534 - 252
= 282 km
Time that Howard needed to reach his destination after the two met
= 282 ÷ 84
= 3
3084 = 3
514 h
Answer(s): (a) 94 km/h; (b) 3
514 h