City C and City D are 480 km apart. At 6.22 p.m., Fabian is travelling at a uniform speed left City C for City D while Paul set off from City D to City C along the same road at a uniform speed, which was 8 km/h slower than that of Fabian. The two met at 9.22 p.m.

1. Find the speed of Fabian.
2. If Paul continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Fabian and Paul to travel from 6.22 p.m. to 9.22 p.m. = 3 h

Average speed of Fabian and Paul
= 480 ÷ 3
= 160 km/h

Fabian's speed
= (160 + 8) ÷ 2
= 168 ÷ 2 
= 84 km/h

(b)
Paul's speed
= 84 - 8
= 76 km/h

Distance that Paul travelled in 3 h
= 3 x 76
= 228 km

Remaining distance that Paul needed to travel
= 480 - 228
= 252 km

Time that Paul needed to reach his destination after the two met
= 252 ÷ 76
= 3²⁴₇₆
= 3⁶₁₉ h

Answer(s): (a) 84 km/h; (b) 3⁶₁₉ h