City D and City E are 552 km apart. At 1.14 p.m., Brandon is travelling at a uniform speed left City D for City E while Jeremy set off from City E to City D along the same road at a uniform speed, which was 6 km/h slower than that of Brandon. The two met at 5.14 p.m.
- Find the speed of Brandon.
- If Jeremy continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Brandon and Jeremy to travel from 1.14 p.m. to 5.14 p.m. = 4 h
Average speed of Brandon and Jeremy
= 552 ÷ 4
= 138 km/h
Brandon's speed
= (138 + 6) ÷ 2
= 144 ÷ 2
= 72 km/h
(b)
Jeremy's speed
= 72 - 6
= 66 km/h
Distance that Jeremy travelled in 4 h
= 4 x 66
= 264 km
Remaining distance that Jeremy needed to travel
= 552 - 264
= 288 km
Time that Jeremy needed to reach his destination after the two met
= 288 ÷ 66
= 4
2466 = 4
411 h
Answer(s): (a) 72 km/h; (b) 4
411 h