City V and City W are 508 km apart. At 2.16 p.m., Ryan is travelling at a uniform speed left City V for City W while Will set off from City W to City V along the same road at a uniform speed, which was 7 km/h slower than that of Ryan. The two met at 6.16 p.m.
- Find the speed of Ryan.
- If Will continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Ryan and Will to travel from 2.16 p.m. to 6.16 p.m. = 4 h
Average speed of Ryan and Will
= 508 ÷ 4
= 127 km/h
Ryan's speed
= (127 + 7) ÷ 2
= 134 ÷ 2
= 67 km/h
(b)
Will's speed
= 67 - 7
= 60 km/h
Distance that Will travelled in 4 h
= 4 x 60
= 240 km
Remaining distance that Will needed to travel
= 508 - 240
= 268 km
Time that Will needed to reach his destination after the two met
= 268 ÷ 60
= 4
2860 = 4
715 h
Answer(s): (a) 67 km/h; (b) 4
715 h