City U and City V are 564 km apart. At 3.20 p.m., Brandon is travelling at a uniform speed left City U for City V while Flynn set off from City V to City U along the same road at a uniform speed, which was 8 km/h slower than that of Brandon. The two met at 6.20 p.m.
- Find the speed of Brandon.
- If Flynn continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Brandon and Flynn to travel from 3.20 p.m. to 6.20 p.m. = 3 h
Average speed of Brandon and Flynn
= 564 ÷ 3
= 188 km/h
Brandon's speed
= (188 + 8) ÷ 2
= 196 ÷ 2
= 98 km/h
(b)
Flynn's speed
= 98 - 8
= 90 km/h
Distance that Flynn travelled in 3 h
= 3 x 90
= 270 km
Remaining distance that Flynn needed to travel
= 564 - 270
= 294 km
Time that Flynn needed to reach his destination after the two met
= 294 ÷ 90
= 3
2490 = 3
415 h
Answer(s): (a) 98 km/h; (b) 3
415 h