City Z and City A are 430 km apart. At 3.42 p.m., Vincent is travelling at a uniform speed left City Z for City A while Elijah set off from City A to City Z along the same road at a uniform speed, which was 5 km/h slower than that of Vincent. The two met at 5.42 p.m.

1. Find the speed of Vincent.
2. If Elijah continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Vincent and Elijah to travel from 3.42 p.m. to 5.42 p.m. = 2 h

Average speed of Vincent and Elijah
= 430 ÷ 2
= 215 km/h

Vincent's speed
= (215 + 5) ÷ 2
= 220 ÷ 2 
= 110 km/h

(b)
Elijah's speed
= 110 - 5
= 105 km/h

Distance that Elijah travelled in 2 h
= 2 x 105
= 210 km

Remaining distance that Elijah needed to travel
= 430 - 210
= 220 km

Time that Elijah needed to reach his destination after the two met
= 220 ÷ 105
= 2¹⁰₁₀₅
= 2²₂₁ h

Answer(s): (a) 110 km/h; (b) 2²₂₁ h