City S and City T are 402 km apart. At 5.51 p.m., Warren is travelling at a uniform speed left City S for City T while Carl set off from City T to City S along the same road at a uniform speed, which was 9 km/h slower than that of Warren. The two met at 7.51 p.m.
- Find the speed of Warren.
- If Carl continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Warren and Carl to travel from 5.51 p.m. to 7.51 p.m. = 2 h
Average speed of Warren and Carl
= 402 ÷ 2
= 201 km/h
Warren's speed
= (201 + 9) ÷ 2
= 210 ÷ 2
= 105 km/h
(b)
Carl's speed
= 105 - 9
= 96 km/h
Distance that Carl travelled in 2 h
= 2 x 96
= 192 km
Remaining distance that Carl needed to travel
= 402 - 192
= 210 km
Time that Carl needed to reach his destination after the two met
= 210 ÷ 96
= 2
1896 = 2
316 h
Answer(s): (a) 105 km/h; (b) 2
316 h