City C and City D are 476 km apart. At 5.28 p.m., Will is travelling at a uniform speed left City C for City D while Peter set off from City D to City C along the same road at a uniform speed, which was 7 km/h slower than that of Will. The two met at 9.28 p.m.
- Find the speed of Will.
- If Peter continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Will and Peter to travel from 5.28 p.m. to 9.28 p.m. = 4 h
Average speed of Will and Peter
= 476 ÷ 4
= 119 km/h
Will's speed
= (119 + 7) ÷ 2
= 126 ÷ 2
= 63 km/h
(b)
Peter's speed
= 63 - 7
= 56 km/h
Distance that Peter travelled in 4 h
= 4 x 56
= 224 km
Remaining distance that Peter needed to travel
= 476 - 224
= 252 km
Time that Peter needed to reach his destination after the two met
= 252 ÷ 56
= 4
2856 = 4
12 h
Answer(s): (a) 63 km/h; (b) 4
12 h