City U and City V are 600 km apart. At 2.55 p.m., Bryan is travelling at a uniform speed left City U for City V while Asher set off from City V to City U along the same road at a uniform speed, which was 10 km/h slower than that of Bryan. The two met at 5.55 p.m.
- Find the speed of Bryan.
- If Asher continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Bryan and Asher to travel from 2.55 p.m. to 5.55 p.m. = 3 h
Average speed of Bryan and Asher
= 600 ÷ 3
= 200 km/h
Bryan's speed
= (200 + 10) ÷ 2
= 210 ÷ 2
= 105 km/h
(b)
Asher's speed
= 105 - 10
= 95 km/h
Distance that Asher travelled in 3 h
= 3 x 95
= 285 km
Remaining distance that Asher needed to travel
= 600 - 285
= 315 km
Time that Asher needed to reach his destination after the two met
= 315 ÷ 95
= 3
3095 = 3
619 h
Answer(s): (a) 105 km/h; (b) 3
619 h