City U and City V are 560 km apart. At 5.29 p.m., Lee is travelling at a uniform speed left City U for City V while Brandon set off from City V to City U along the same road at a uniform speed, which was 12 km/h slower than that of Lee. The two met at 10.29 p.m.

1. Find the speed of Lee.
2. If Brandon continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Lee and Brandon to travel from 5.29 p.m. to 10.29 p.m. = 5 h

Average speed of Lee and Brandon
= 560 ÷ 5
= 112 km/h

Lee's speed
= (112 + 12) ÷ 2
= 124 ÷ 2 
= 62 km/h

(b)
Brandon's speed
= 62 - 12
= 50 km/h

Distance that Brandon travelled in 5 h
= 5 x 50
= 250 km

Remaining distance that Brandon needed to travel
= 560 - 250
= 310 km

Time that Brandon needed to reach his destination after the two met
= 310 ÷ 50
= 6¹⁰₅₀
= 6¹₅ h

Answer(s): (a) 62 km/h; (b) 6¹₅ h