City W and City X are 556 km apart. At 2.14 p.m., Wesley is travelling at a uniform speed left City W for City X while Fred set off from City X to City W along the same road at a uniform speed, which was 11 km/h slower than that of Wesley. The two met at 6.14 p.m.

1. Find the speed of Wesley.
2. If Fred continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Wesley and Fred to travel from 2.14 p.m. to 6.14 p.m. = 4 h

Average speed of Wesley and Fred
= 556 ÷ 4
= 139 km/h

Wesley's speed
= (139 + 11) ÷ 2
= 150 ÷ 2 
= 75 km/h

(b)
Fred's speed
= 75 - 11
= 64 km/h

Distance that Fred travelled in 4 h
= 4 x 64
= 256 km

Remaining distance that Fred needed to travel
= 556 - 256
= 300 km

Time that Fred needed to reach his destination after the two met
= 300 ÷ 64
= 4⁴⁴₆₄
= 4¹¹₁₆ h

Answer(s): (a) 75 km/h; (b) 4¹¹₁₆ h