At 09 10, Xuan left Town Q and cycled towards Town R. Roshel left Town Q and cycled towards Town R at 09 25. Roshel's cycling speed was 4 km/h faster than Xuan. At 11 10, Roshel caught up with Xuan. Find the cycling speed of each cyclist.
- Xuan
- Roshel
(a)
Duration that Roshel cycled from 09 25 to 11 10
= 1
4560 = 1
34 h
Distance that Roshel cycled more than Xuan
= 1
34 x 4
= 7 km
However, since Xuan left 15 minutes earlier than Roshel and Roshel caught up with Xuan, it means that Xuan has cycled 7 km in 15 min.
1 h = 60 min
15 min = 15 ÷ 60 =
14 h
Xuan's cycling speed
= 7 ÷
14 = 7 x
41 = 28 km/h
(b)
Roshel's cycling speed
= 28 + 4
= 32 km/h
Answer(s): (a) 28 km/h ; (b) 32 km/h
