At 09 20, Jade left Town N and cycled towards Town P. Lynn left Town N and cycled towards Town P at 09 40. Lynn's cycling speed was 3 km/h faster than Jade. At 13 20, Lynn caught up with Jade. Find the cycling speed of each cyclist.
- Jade
- Lynn
(a)
Duration that Lynn cycled from 09 40 to 13 20
= 3
4060 = 3
23 h
Distance that Lynn cycled more than Jade
= 3
23 x 3
= 11 km
However, since Jade left 20 minutes earlier than Lynn and Lynn caught up with Jade, it means that Jade has cycled 11 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Jade's cycling speed
= 11 ÷
13 = 11 x
31 = 33 km/h
(b)
Lynn's cycling speed
= 33 + 3
= 36 km/h
Answer(s): (a) 33 km/h ; (b) 36 km/h
