At 06 20, Gillian left Town E and cycled towards Town F. Cathy left Town E and cycled towards Town F at 06 50. Cathy's cycling speed was 2 km/h faster than Gillian. At 12 20, Cathy caught up with Gillian. Find the cycling speed of each cyclist.

1. Gillian
2. Cathy

(a)
Duration that Cathy cycled from 06 50 to 12 20
= 5³⁰₆₀
= 5¹₂ h

Distance that Cathy cycled more than Gillian
= 5¹₂ x 2
= 11 km

However, since Gillian left 30 minutes earlier than Cathy and Cathy caught up with Gillian, it means that Gillian has cycled 11 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Gillian's cycling speed
= 11 ÷ ¹₂
= 11 x ²₁
= 22 km/h

(b)
Cathy's cycling speed
= 22 + 2
= 24 km/h

Answer(s): (a) 22 km/h ; (b) 24 km/h