At 05 20, Fanny left Town T and cycled towards Town U. Nora left Town T and cycled towards Town U at 05 50. Nora's cycling speed was 2 km/h faster than Fanny. At 11 20, Nora caught up with Fanny. Find the cycling speed of each cyclist.
- Fanny
- Nora
(a)
Duration that Nora cycled from 05 50 to 11 20
= 5
3060 = 5
12 h
Distance that Nora cycled more than Fanny
= 5
12 x 2
= 11 km
However, since Fanny left 30 minutes earlier than Nora and Nora caught up with Fanny, it means that Fanny has cycled 11 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Fanny's cycling speed
= 11 ÷
12 = 11 x
21 = 22 km/h
(b)
Nora's cycling speed
= 22 + 2
= 24 km/h
Answer(s): (a) 22 km/h ; (b) 24 km/h
