At 05 15, Roshel left Town A and cycled towards Town B. Sabrina left Town A and cycled towards Town B at 05 55. Sabrina's cycling speed was 3 km/h faster than Roshel. At 11 15, Sabrina caught up with Roshel. Find the cycling speed of each cyclist.

1. Roshel
2. Sabrina

(a)
Duration that Sabrina cycled from 05 55 to 11 15
= 5²⁰₆₀
= 5¹₃ h

Distance that Sabrina cycled more than Roshel
= 5¹₃ x 3
= 16 km

However, since Roshel left 40 minutes earlier than Sabrina and Sabrina caught up with Roshel, it means that Roshel has cycled 16 km in 40 min.

1 h = 60 min 
40 min = 40 ÷ 60 = ²₃ h

Roshel's cycling speed
= 16 ÷ ²₃
= 16 x ³₂
= 24 km/h

(b)
Sabrina's cycling speed
= 24 + 3
= 27 km/h

Answer(s): (a) 24 km/h ; (b) 27 km/h