At 08 15, Sabrina left Town Y and cycled towards Town Z. Fanny left Town Y and cycled towards Town Z at 08 55. Fanny's cycling speed was 3 km/h faster than Sabrina. At 10 15, Fanny caught up with Sabrina. Find the cycling speed of each cyclist.

1. Sabrina
2. Fanny

(a)
Duration that Fanny cycled from 08 55 to 10 15
= 1²⁰₆₀
= 1¹₃ h

Distance that Fanny cycled more than Sabrina
= 1¹₃ x 3
= 4 km

However, since Sabrina left 40 minutes earlier than Fanny and Fanny caught up with Sabrina, it means that Sabrina has cycled 4 km in 40 min.

1 h = 60 min 
40 min = 40 ÷ 60 = ²₃ h

Sabrina's cycling speed
= 4 ÷ ²₃
= 4 x ³₂
= 6 km/h

(b)
Fanny's cycling speed
= 6 + 3
= 9 km/h

Answer(s): (a) 6 km/h ; (b) 9 km/h