At 05 15, Fanny left Town J and cycled towards Town K. Winnie left Town J and cycled towards Town K at 05 45. Winnie's cycling speed was 2 km/h faster than Fanny. At 12 15, Winnie caught up with Fanny. Find the cycling speed of each cyclist.

1. Fanny
2. Winnie

(a)
Duration that Winnie cycled from 05 45 to 12 15
= 6³⁰₆₀
= 6¹₂ h

Distance that Winnie cycled more than Fanny
= 6¹₂ x 2
= 13 km

However, since Fanny left 30 minutes earlier than Winnie and Winnie caught up with Fanny, it means that Fanny has cycled 13 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Fanny's cycling speed
= 13 ÷ ¹₂
= 13 x ²₁
= 26 km/h

(b)
Winnie's cycling speed
= 26 + 2
= 28 km/h

Answer(s): (a) 26 km/h ; (b) 28 km/h