At 08 10, Gillian left Town E and cycled towards Town F. Xylia left Town E and cycled towards Town F at 08 50. Xylia's cycling speed was 3 km/h faster than Gillian. At 14 10, Xylia caught up with Gillian. Find the cycling speed of each cyclist.

1. Gillian
2. Xylia

(a)
Duration that Xylia cycled from 08 50 to 14 10
= 5²⁰₆₀
= 5¹₃ h

Distance that Xylia cycled more than Gillian
= 5¹₃ x 3
= 16 km

However, since Gillian left 40 minutes earlier than Xylia and Xylia caught up with Gillian, it means that Gillian has cycled 16 km in 40 min.

1 h = 60 min 
40 min = 40 ÷ 60 = ²₃ h

Gillian's cycling speed
= 16 ÷ ²₃
= 16 x ³₂
= 24 km/h

(b)
Xylia's cycling speed
= 24 + 3
= 27 km/h

Answer(s): (a) 24 km/h ; (b) 27 km/h