At 07 20, Anna left Town N and cycled towards Town P. Tiffany left Town N and cycled towards Town P at 07 50. Tiffany's cycling speed was 2 km/h faster than Anna. At 10 20, Tiffany caught up with Anna. Find the cycling speed of each cyclist.
- Anna
- Tiffany
(a)
Duration that Tiffany cycled from 07 50 to 10 20
= 2
3060 = 2
12 h
Distance that Tiffany cycled more than Anna
= 2
12 x 2
= 5 km
However, since Anna left 30 minutes earlier than Tiffany and Tiffany caught up with Anna, it means that Anna has cycled 5 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Anna's cycling speed
= 5 ÷
12 = 5 x
21 = 10 km/h
(b)
Tiffany's cycling speed
= 10 + 2
= 12 km/h
Answer(s): (a) 10 km/h ; (b) 12 km/h
