At 09 25, Linda left Town J and cycled towards Town K. Gem left Town J and cycled towards Town K at 09 55. Gem's cycling speed was 6 km/h faster than Linda. At 11 25, Gem caught up with Linda. Find the cycling speed of each cyclist.
- Linda
- Gem
(a)
Duration that Gem cycled from 09 55 to 11 25
= 1
3060 = 1
12 h
Distance that Gem cycled more than Linda
= 1
12 x 6
= 9 km
However, since Linda left 30 minutes earlier than Gem and Gem caught up with Linda, it means that Linda has cycled 9 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Linda's cycling speed
= 9 ÷
12 = 9 x
21 = 18 km/h
(b)
Gem's cycling speed
= 18 + 6
= 24 km/h
Answer(s): (a) 18 km/h ; (b) 24 km/h
