At 08 10, Winnie left Town R and cycled towards Town S. Fanny left Town R and cycled towards Town S at 08 40. Fanny's cycling speed was 8 km/h faster than Winnie. At 10 10, Fanny caught up with Winnie. Find the cycling speed of each cyclist.

1. Winnie
2. Fanny

(a)
Duration that Fanny cycled from 08 40 to 10 10
= 1³⁰₆₀
= 1¹₂ h

Distance that Fanny cycled more than Winnie
= 1¹₂ x 8
= 12 km

However, since Winnie left 30 minutes earlier than Fanny and Fanny caught up with Winnie, it means that Winnie has cycled 12 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Winnie's cycling speed
= 12 ÷ ¹₂
= 12 x ²₁
= 24 km/h

(b)
Fanny's cycling speed
= 24 + 8
= 32 km/h

Answer(s): (a) 24 km/h ; (b) 32 km/h