At 08 10, Usha left Town S and cycled towards Town T. Tina left Town S and cycled towards Town T at 08 30. Tina's cycling speed was 3 km/h faster than Usha. At 11 10, Tina caught up with Usha. Find the cycling speed of each cyclist.
- Usha
- Tina
(a)
Duration that Tina cycled from 08 30 to 11 10
= 2
4060 = 2
23 h
Distance that Tina cycled more than Usha
= 2
23 x 3
= 8 km
However, since Usha left 20 minutes earlier than Tina and Tina caught up with Usha, it means that Usha has cycled 8 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Usha's cycling speed
= 8 ÷
13 = 8 x
31 = 24 km/h
(b)
Tina's cycling speed
= 24 + 3
= 27 km/h
Answer(s): (a) 24 km/h ; (b) 27 km/h
