At 06 10, Shannon left Town A and cycled towards Town B. Betty left Town A and cycled towards Town B at 06 40. Betty's cycling speed was 2 km/h faster than Shannon. At 14 10, Betty caught up with Shannon. Find the cycling speed of each cyclist.

1. Shannon
2. Betty

(a)
Duration that Betty cycled from 06 40 to 14 10
= 7³⁰₆₀
= 7¹₂ h

Distance that Betty cycled more than Shannon
= 7¹₂ x 2
= 15 km

However, since Shannon left 30 minutes earlier than Betty and Betty caught up with Shannon, it means that Shannon has cycled 15 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Shannon's cycling speed
= 15 ÷ ¹₂
= 15 x ²₁
= 30 km/h

(b)
Betty's cycling speed
= 30 + 2
= 32 km/h

Answer(s): (a) 30 km/h ; (b) 32 km/h