At 08 35, Jaslyn left Town T and cycled towards Town U. Opal left Town T and cycled towards Town U at 08 55. Opal's cycling speed was 3 km/h faster than Jaslyn. At 11 35, Opal caught up with Jaslyn. Find the cycling speed of each cyclist.
- Jaslyn
- Opal
(a)
Duration that Opal cycled from 08 55 to 11 35
= 2
4060 = 2
23 h
Distance that Opal cycled more than Jaslyn
= 2
23 x 3
= 8 km
However, since Jaslyn left 20 minutes earlier than Opal and Opal caught up with Jaslyn, it means that Jaslyn has cycled 8 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Jaslyn's cycling speed
= 8 ÷
13 = 8 x
31 = 24 km/h
(b)
Opal's cycling speed
= 24 + 3
= 27 km/h
Answer(s): (a) 24 km/h ; (b) 27 km/h
