At 07 20, Esther left Town W and cycled towards Town X. Pamela left Town W and cycled towards Town X at 07 50. Pamela's cycling speed was 2 km/h faster than Esther. At 15 20, Pamela caught up with Esther. Find the cycling speed of each cyclist.

1. Esther
2. Pamela

(a)
Duration that Pamela cycled from 07 50 to 15 20
= 7³⁰₆₀
= 7¹₂ h

Distance that Pamela cycled more than Esther
= 7¹₂ x 2
= 15 km

However, since Esther left 30 minutes earlier than Pamela and Pamela caught up with Esther, it means that Esther has cycled 15 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Esther's cycling speed
= 15 ÷ ¹₂
= 15 x ²₁
= 30 km/h

(b)
Pamela's cycling speed
= 30 + 2
= 32 km/h

Answer(s): (a) 30 km/h ; (b) 32 km/h