At 06 25, Opal left Town B and cycled towards Town C. Betty left Town B and cycled towards Town C at 06 55. Betty's cycling speed was 2 km/h faster than Opal. At 14 25, Betty caught up with Opal. Find the cycling speed of each cyclist.
- Opal
- Betty
(a)
Duration that Betty cycled from 06 55 to 14 25
= 7
3060 = 7
12 h
Distance that Betty cycled more than Opal
= 7
12 x 2
= 15 km
However, since Opal left 30 minutes earlier than Betty and Betty caught up with Opal, it means that Opal has cycled 15 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Opal's cycling speed
= 15 ÷
12 = 15 x
21 = 30 km/h
(b)
Betty's cycling speed
= 30 + 2
= 32 km/h
Answer(s): (a) 30 km/h ; (b) 32 km/h
