At 09 30, Jaslyn left Town Z and cycled towards Town A. Xylia left Town Z and cycled towards Town A at 09 45. Xylia's cycling speed was 4 km/h faster than Jaslyn. At 11 30, Xylia caught up with Jaslyn. Find the cycling speed of each cyclist.
- Jaslyn
- Xylia
(a)
Duration that Xylia cycled from 09 45 to 11 30
= 1
4560 = 1
34 h
Distance that Xylia cycled more than Jaslyn
= 1
34 x 4
= 7 km
However, since Jaslyn left 15 minutes earlier than Xylia and Xylia caught up with Jaslyn, it means that Jaslyn has cycled 7 km in 15 min.
1 h = 60 min
15 min = 15 ÷ 60 =
14 h
Jaslyn's cycling speed
= 7 ÷
14 = 7 x
41 = 28 km/h
(b)
Xylia's cycling speed
= 28 + 4
= 32 km/h
Answer(s): (a) 28 km/h ; (b) 32 km/h
