At 05 25, Opal left Town W and cycled towards Town X. Betty left Town W and cycled towards Town X at 05 55. Betty's cycling speed was 2 km/h faster than Opal. At 14 25, Betty caught up with Opal. Find the cycling speed of each cyclist.
- Opal
- Betty
(a)
Duration that Betty cycled from 05 55 to 14 25
= 8
3060 = 8
12 h
Distance that Betty cycled more than Opal
= 8
12 x 2
= 17 km
However, since Opal left 30 minutes earlier than Betty and Betty caught up with Opal, it means that Opal has cycled 17 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Opal's cycling speed
= 17 ÷
12 = 17 x
21 = 34 km/h
(b)
Betty's cycling speed
= 34 + 2
= 36 km/h
Answer(s): (a) 34 km/h ; (b) 36 km/h
