At 05 25, Tina left Town K and cycled towards Town L. Raeann left Town K and cycled towards Town L at 05 55. Raeann's cycling speed was 2 km/h faster than Tina. At 12 25, Raeann caught up with Tina. Find the cycling speed of each cyclist.
- Tina
- Raeann
(a)
Duration that Raeann cycled from 05 55 to 12 25
= 6
3060 = 6
12 h
Distance that Raeann cycled more than Tina
= 6
12 x 2
= 13 km
However, since Tina left 30 minutes earlier than Raeann and Raeann caught up with Tina, it means that Tina has cycled 13 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Tina's cycling speed
= 13 ÷
12 = 13 x
21 = 26 km/h
(b)
Raeann's cycling speed
= 26 + 2
= 28 km/h
Answer(s): (a) 26 km/h ; (b) 28 km/h
