At 08 15, Joelle left Town V and cycled towards Town W. Marion left Town V and cycled towards Town W at 08 45. Marion's cycling speed was 6 km/h faster than Joelle. At 10 15, Marion caught up with Joelle. Find the cycling speed of each cyclist.

1. Joelle
2. Marion

(a)
Duration that Marion cycled from 08 45 to 10 15
= 1³⁰₆₀
= 1¹₂ h

Distance that Marion cycled more than Joelle
= 1¹₂ x 6
= 9 km

However, since Joelle left 30 minutes earlier than Marion and Marion caught up with Joelle, it means that Joelle has cycled 9 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Joelle's cycling speed
= 9 ÷ ¹₂
= 9 x ²₁
= 18 km/h

(b)
Marion's cycling speed
= 18 + 6
= 24 km/h

Answer(s): (a) 18 km/h ; (b) 24 km/h