At 06 25, Jaslyn left Town S and cycled towards Town T. Mary left Town S and cycled towards Town T at 06 55. Mary's cycling speed was 2 km/h faster than Jaslyn. At 14 25, Mary caught up with Jaslyn. Find the cycling speed of each cyclist.
- Jaslyn
- Mary
(a)
Duration that Mary cycled from 06 55 to 14 25
= 7
3060 = 7
12 h
Distance that Mary cycled more than Jaslyn
= 7
12 x 2
= 15 km
However, since Jaslyn left 30 minutes earlier than Mary and Mary caught up with Jaslyn, it means that Jaslyn has cycled 15 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Jaslyn's cycling speed
= 15 ÷
12 = 15 x
21 = 30 km/h
(b)
Mary's cycling speed
= 30 + 2
= 32 km/h
Answer(s): (a) 30 km/h ; (b) 32 km/h
