At 08 10, Kimberly left Town K and cycled towards Town L. Opal left Town K and cycled towards Town L at 08 55. Opal's cycling speed was 4 km/h faster than Kimberly. At 11 10, Opal caught up with Kimberly. Find the cycling speed of each cyclist.

1. Kimberly
2. Opal

(a)
Duration that Opal cycled from 08 55 to 11 10
= 2¹⁵₆₀
= 2¹₄ h

Distance that Opal cycled more than Kimberly
= 2¹₄ x 4
= 9 km

However, since Kimberly left 45 minutes earlier than Opal and Opal caught up with Kimberly, it means that Kimberly has cycled 9 km in 45 min.

1 h = 60 min 
45 min = 45 ÷ 60 = ³₄ h

Kimberly's cycling speed
= 9 ÷ ³₄
= 9 x ⁴₃
= 12 km/h

(b)
Opal's cycling speed
= 12 + 4
= 16 km/h

Answer(s): (a) 12 km/h ; (b) 16 km/h