At 09 25, Tina left Town D and cycled towards Town E. Xylia left Town D and cycled towards Town E at 09 45. Xylia's cycling speed was 3 km/h faster than Tina. At 11 25, Xylia caught up with Tina. Find the cycling speed of each cyclist.
- Tina
- Xylia
(a)
Duration that Xylia cycled from 09 45 to 11 25
= 1
4060 = 1
23 h
Distance that Xylia cycled more than Tina
= 1
23 x 3
= 5 km
However, since Tina left 20 minutes earlier than Xylia and Xylia caught up with Tina, it means that Tina has cycled 5 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Tina's cycling speed
= 5 ÷
13 = 5 x
31 = 15 km/h
(b)
Xylia's cycling speed
= 15 + 3
= 18 km/h
Answer(s): (a) 15 km/h ; (b) 18 km/h
