At 06 10, Risa left Town B and cycled towards Town C. Abi left Town B and cycled towards Town C at 06 30. Abi's cycling speed was 3 km/h faster than Risa. At 10 10, Abi caught up with Risa. Find the cycling speed of each cyclist.
- Risa
- Abi
(a)
Duration that Abi cycled from 06 30 to 10 10
= 3
4060 = 3
23 h
Distance that Abi cycled more than Risa
= 3
23 x 3
= 11 km
However, since Risa left 20 minutes earlier than Abi and Abi caught up with Risa, it means that Risa has cycled 11 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Risa's cycling speed
= 11 ÷
13 = 11 x
31 = 33 km/h
(b)
Abi's cycling speed
= 33 + 3
= 36 km/h
Answer(s): (a) 33 km/h ; (b) 36 km/h
