At 06 25, Marion left Town P and cycled towards Town Q. Barbara left Town P and cycled towards Town Q at 06 55. Barbara's cycling speed was 2 km/h faster than Marion. At 12 25, Barbara caught up with Marion. Find the cycling speed of each cyclist.

1. Marion
2. Barbara

(a)
Duration that Barbara cycled from 06 55 to 12 25
= 5³⁰₆₀
= 5¹₂ h

Distance that Barbara cycled more than Marion
= 5¹₂ x 2
= 11 km

However, since Marion left 30 minutes earlier than Barbara and Barbara caught up with Marion, it means that Marion has cycled 11 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Marion's cycling speed
= 11 ÷ ¹₂
= 11 x ²₁
= 22 km/h

(b)
Barbara's cycling speed
= 22 + 2
= 24 km/h

Answer(s): (a) 22 km/h ; (b) 24 km/h