At 09 25, Xandra left Town A and cycled towards Town B. Esther left Town A and cycled towards Town B at 09 55. Esther's cycling speed was 10 km/h faster than Xandra. At 11 25, Esther caught up with Xandra. Find the cycling speed of each cyclist.
- Xandra
- Esther
(a)
Duration that Esther cycled from 09 55 to 11 25
= 1
3060 = 1
12 h
Distance that Esther cycled more than Xandra
= 1
12 x 10
= 15 km
However, since Xandra left 30 minutes earlier than Esther and Esther caught up with Xandra, it means that Xandra has cycled 15 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Xandra's cycling speed
= 15 ÷
12 = 15 x
21 = 30 km/h
(b)
Esther's cycling speed
= 30 + 10
= 40 km/h
Answer(s): (a) 30 km/h ; (b) 40 km/h