At 09 15, Opal left Town X and cycled towards Town Y. Abi left Town X and cycled towards Town Y at 09 45. Abi's cycling speed was 8 km/h faster than Opal. At 11 15, Abi caught up with Opal. Find the cycling speed of each cyclist.
- Opal
- Abi
(a)
Duration that Abi cycled from 09 45 to 11 15
= 1
3060 = 1
12 h
Distance that Abi cycled more than Opal
= 1
12 x 8
= 12 km
However, since Opal left 30 minutes earlier than Abi and Abi caught up with Opal, it means that Opal has cycled 12 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Opal's cycling speed
= 12 ÷
12 = 12 x
21 = 24 km/h
(b)
Abi's cycling speed
= 24 + 8
= 32 km/h
Answer(s): (a) 24 km/h ; (b) 32 km/h
