At 08 20, Wendy left Town V and cycled towards Town W. Ivory left Town V and cycled towards Town W at 08 50. Ivory's cycling speed was 2 km/h faster than Wendy. At 10 20, Ivory caught up with Wendy. Find the cycling speed of each cyclist.
- Wendy
- Ivory
(a)
Duration that Ivory cycled from 08 50 to 10 20
= 1
3060 = 1
12 h
Distance that Ivory cycled more than Wendy
= 1
12 x 2
= 3 km
However, since Wendy left 30 minutes earlier than Ivory and Ivory caught up with Wendy, it means that Wendy has cycled 3 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Wendy's cycling speed
= 3 ÷
12 = 3 x
21 = 6 km/h
(b)
Ivory's cycling speed
= 6 + 2
= 8 km/h
Answer(s): (a) 6 km/h ; (b) 8 km/h
