At 06 25, Gem left Town H and cycled towards Town J. Kathy left Town H and cycled towards Town J at 06 45. Kathy's cycling speed was 3 km/h faster than Gem. At 10 25, Kathy caught up with Gem. Find the cycling speed of each cyclist.
- Gem
- Kathy
(a)
Duration that Kathy cycled from 06 45 to 10 25
= 3
4060 = 3
23 h
Distance that Kathy cycled more than Gem
= 3
23 x 3
= 11 km
However, since Gem left 20 minutes earlier than Kathy and Kathy caught up with Gem, it means that Gem has cycled 11 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Gem's cycling speed
= 11 ÷
13 = 11 x
31 = 33 km/h
(b)
Kathy's cycling speed
= 33 + 3
= 36 km/h
Answer(s): (a) 33 km/h ; (b) 36 km/h
