At 05 15, Min left Town P and cycled towards Town Q. Jade left Town P and cycled towards Town Q at 05 45. Jade's cycling speed was 2 km/h faster than Min. At 15 15, Jade caught up with Min. Find the cycling speed of each cyclist.
- Min
- Jade
(a)
Duration that Jade cycled from 05 45 to 15 15
= 9
3060 = 9
12 h
Distance that Jade cycled more than Min
= 9
12 x 2
= 19 km
However, since Min left 30 minutes earlier than Jade and Jade caught up with Min, it means that Min has cycled 19 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Min's cycling speed
= 19 ÷
12 = 19 x
21 = 38 km/h
(b)
Jade's cycling speed
= 38 + 2
= 40 km/h
Answer(s): (a) 38 km/h ; (b) 40 km/h
