At 05 10, Cindy left Town Q and cycled towards Town R. Esther left Town Q and cycled towards Town R at 05 40. Esther's cycling speed was 2 km/h faster than Cindy. At 15 10, Esther caught up with Cindy. Find the cycling speed of each cyclist.

1. Cindy
2. Esther

(a)
Duration that Esther cycled from 05 40 to 15 10
= 9³⁰₆₀
= 9¹₂ h

Distance that Esther cycled more than Cindy
= 9¹₂ x 2
= 19 km

However, since Cindy left 30 minutes earlier than Esther and Esther caught up with Cindy, it means that Cindy has cycled 19 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Cindy's cycling speed
= 19 ÷ ¹₂
= 19 x ²₁
= 38 km/h

(b)
Esther's cycling speed
= 38 + 2
= 40 km/h

Answer(s): (a) 38 km/h ; (b) 40 km/h