At 09 15, Marion left Town M and cycled towards Town N. Nora left Town M and cycled towards Town N at 09 30. Nora's cycling speed was 4 km/h faster than Marion. At 11 15, Nora caught up with Marion. Find the cycling speed of each cyclist.
- Marion
- Nora
(a)
Duration that Nora cycled from 09 30 to 11 15
= 1
4560 = 1
34 h
Distance that Nora cycled more than Marion
= 1
34 x 4
= 7 km
However, since Marion left 15 minutes earlier than Nora and Nora caught up with Marion, it means that Marion has cycled 7 km in 15 min.
1 h = 60 min
15 min = 15 ÷ 60 =
14 h
Marion's cycling speed
= 7 ÷
14 = 7 x
41 = 28 km/h
(b)
Nora's cycling speed
= 28 + 4
= 32 km/h
Answer(s): (a) 28 km/h ; (b) 32 km/h
