At 09 30, Victoria left Town D and cycled towards Town E. Mary left Town D and cycled towards Town E at 09 50. Mary's cycling speed was 6 km/h faster than Victoria. At 11 30, Mary caught up with Victoria. Find the cycling speed of each cyclist.

1. Victoria
2. Mary

(a)
Duration that Mary cycled from 09 50 to 11 30
= 1⁴⁰₆₀
= 1²₃ h

Distance that Mary cycled more than Victoria
= 1²₃ x 6
= 10 km

However, since Victoria left 20 minutes earlier than Mary and Mary caught up with Victoria, it means that Victoria has cycled 10 km in 20 min.

1 h = 60 min 
20 min = 20 ÷ 60 = ¹₃ h

Victoria's cycling speed
= 10 ÷ ¹₃
= 10 x ³₁
= 30 km/h

(b)
Mary's cycling speed
= 30 + 6
= 36 km/h

Answer(s): (a) 30 km/h ; (b) 36 km/h