At 09 20, Irene left Town S and cycled towards Town T. Raeann left Town S and cycled towards Town T at 09 40. Raeann's cycling speed was 3 km/h faster than Irene. At 11 20, Raeann caught up with Irene. Find the cycling speed of each cyclist.
- Irene
- Raeann
(a)
Duration that Raeann cycled from 09 40 to 11 20
= 1
4060 = 1
23 h
Distance that Raeann cycled more than Irene
= 1
23 x 3
= 5 km
However, since Irene left 20 minutes earlier than Raeann and Raeann caught up with Irene, it means that Irene has cycled 5 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Irene's cycling speed
= 5 ÷
13 = 5 x
31 = 15 km/h
(b)
Raeann's cycling speed
= 15 + 3
= 18 km/h
Answer(s): (a) 15 km/h ; (b) 18 km/h
