At 08 20, Sabrina left Town D and cycled towards Town E. Cindy left Town D and cycled towards Town E at 08 50. Cindy's cycling speed was 2 km/h faster than Sabrina. At 14 20, Cindy caught up with Sabrina. Find the cycling speed of each cyclist.

1. Sabrina
2. Cindy

(a)
Duration that Cindy cycled from 08 50 to 14 20
= 5³⁰₆₀
= 5¹₂ h

Distance that Cindy cycled more than Sabrina
= 5¹₂ x 2
= 11 km

However, since Sabrina left 30 minutes earlier than Cindy and Cindy caught up with Sabrina, it means that Sabrina has cycled 11 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Sabrina's cycling speed
= 11 ÷ ¹₂
= 11 x ²₁
= 22 km/h

(b)
Cindy's cycling speed
= 22 + 2
= 24 km/h

Answer(s): (a) 22 km/h ; (b) 24 km/h