At 06 30, Xylia left Town N and cycled towards Town P. Gwen left Town N and cycled towards Town P at 06 50. Gwen's cycling speed was 3 km/h faster than Xylia. At 10 30, Gwen caught up with Xylia. Find the cycling speed of each cyclist.
- Xylia
- Gwen
(a)
Duration that Gwen cycled from 06 50 to 10 30
= 3
4060 = 3
23 h
Distance that Gwen cycled more than Xylia
= 3
23 x 3
= 11 km
However, since Xylia left 20 minutes earlier than Gwen and Gwen caught up with Xylia, it means that Xylia has cycled 11 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Xylia's cycling speed
= 11 ÷
13 = 11 x
31 = 33 km/h
(b)
Gwen's cycling speed
= 33 + 3
= 36 km/h
Answer(s): (a) 33 km/h ; (b) 36 km/h
