At 08 20, Jen left Town T and cycled towards Town U. Min left Town T and cycled towards Town U at 08 50. Min's cycling speed was 4 km/h faster than Jen. At 11 20, Min caught up with Jen. Find the cycling speed of each cyclist.
- Jen
- Min
(a)
Duration that Min cycled from 08 50 to 11 20
= 2
3060 = 2
12 h
Distance that Min cycled more than Jen
= 2
12 x 4
= 10 km
However, since Jen left 30 minutes earlier than Min and Min caught up with Jen, it means that Jen has cycled 10 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Jen's cycling speed
= 10 ÷
12 = 10 x
21 = 20 km/h
(b)
Min's cycling speed
= 20 + 4
= 24 km/h
Answer(s): (a) 20 km/h ; (b) 24 km/h
