At 06 10, Hazel left Town A and cycled towards Town B. Shannon left Town A and cycled towards Town B at 06 40. Shannon's cycling speed was 2 km/h faster than Hazel. At 10 10, Shannon caught up with Hazel. Find the cycling speed of each cyclist.

1. Hazel
2. Shannon

(a)
Duration that Shannon cycled from 06 40 to 10 10
= 3³⁰₆₀
= 3¹₂ h

Distance that Shannon cycled more than Hazel
= 3¹₂ x 2
= 7 km

However, since Hazel left 30 minutes earlier than Shannon and Shannon caught up with Hazel, it means that Hazel has cycled 7 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Hazel's cycling speed
= 7 ÷ ¹₂
= 7 x ²₁
= 14 km/h

(b)
Shannon's cycling speed
= 14 + 2
= 16 km/h

Answer(s): (a) 14 km/h ; (b) 16 km/h